10 / 32 · Concept
Inductors connect current change to voltage
Calculate an RL time constant and recognize current continuity.
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Current carries the stored state
For an ideal inductor, voltage is and energy is . Its current cannot jump instantly without an impulse of voltage. At settled DC, an ideal inductor has zero voltage and behaves as a short circuit. A real winding retains resistance and has current-dependent core behavior, so “short at DC” does not mean a lossless wire at any current.
Applying a constant 1 V across 10 mH changes current at 100 A/s. Starting from zero, current rises by 100 mA in 1 ms if the voltage remains constant. Stored energy at 100 mA is μJ. A continuing ramp eventually meets source or component limits; the ideal formula alone does not create a safe maximum current.
Add a resistor
Connect a 3.3 V step to a series 330 Ω resistor and 10 mH inductor. The final current is 10 mA, and the time constant is μs. Starting from zero, . After one time constant, current is 6.3212 mA. The inductor initially takes the full source voltage; its voltage tends toward zero as current settles.
Compare this with the capacitor: capacitor voltage and inductor current are the quantities that remain continuous in finite-source switching. Keeping track of the correct stored state prevents a common error in initial-condition problems.
Opening a path changes the model
If an inductor carrying current is abruptly disconnected, it develops voltage to continue current through whatever parasitic or protective path exists. A flyback diode is a common deliberate path, but its voltage, energy, and decay behavior require a circuit calculation. Do not conclude that an open switch immediately makes stored current zero.
When simulating an RL transition, include series resistance and a physically meaningful current-return path. State whether winding resistance is included in R. A 30.303 μs prediction from nominal values is useful only if the actual total series resistance and inductance match those assumptions.
Try it yourself
A 20 mH inductor with total series resistance 100 Ω is driven by 5 V. Find τ and final current.
Read the explanation
τ = L/R = 200 μs. Final current is 5/100 = 50 mA. At t = τ, current is approximately 31.606 mA for a zero-current start.